Solubility is defined as the greatest amount of solute that may be dissolved in a given amount of solvent to form a saturated solution at a given temperature.
The number of moles of a solute that may be dissolved in one liter of solution is known as molar solubility. It is measured in mol/L or M. (molarity).
PbBr2 is an ionic molecule that breaks down in water to form lead and bromine ions.
The dissociation response is stated as follows:
The solubility product constant is denoted as:
If and where; The Ksp for
In a 0.500 kBr solution; KBr Br Assuming that x = 0; since it is less than 0.500 x = 2.64 × 10⁻⁵ M
As a result, we may deduce that the molar solubility of PbBr₂ in 0.500 KBr solution is 2.64 × 10⁻⁵ M
The following information is provided: The KBr concentration is 0.500 M. Lead (II) bromide has a solubility product of 6.60 times 10…
2 + n o h minus. Also, since there is a 2 in from my calcium, h minus will be squared. That concludes my KSP.
At a particular temperature, the molar solubility of PbBr2 is 2.17 10-3 M.
Lead(II) bromide / Molar mass 367.01 g/mol
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