Given: There will be one roll of the dice.
A die has six sides, each of which is numbered 1, 2, 3, 4, 5, and 6.
If we were to toss one dice, the following are some of the events that may occur: 1, 2, 3, 4, 5 and 6
The total number of possibilities that might occur is equal to six.
Let “E” stand for the possibility of receiving a number higher than four.
The numbers 5, 6, and beyond that appear on a dice are:
The number of outcomes that are favorable to E equals two.
Probability, denoted by the letter “E,” is calculated by dividing the number of favorable outcomes by the total number of outcomes.
P(E) = 2/6 = 1/3
Therefore, the necessary probability of obtaining a number bigger than four, P(E), is equal to one third.
The likelihood of rolling a number that is greater than a certain threshold (e.g. roll more than a 5).
Make more than a… roll.
1 5/6 (83.33 percent )
2 4/6 (66.67 percent )
3 3/6 (50 percent )
4 4/6 (66.667 percent )
As a result, the odds of receiving the number 4 are one in sixty-one.
The number that is both lower than and equal to four is also 4. The possibility of obtaining a number that is not more than four is two-thirds of a chance.
(ii) a) Given that we are aware that a number can only be more than 5 if it is a multiple of 6, the number of possible outcomes of throwing a die and receiving a number that is greater than 5 is one. It conveys the message that the probability of receiving a number that is more than five is one.